Gases having same reduced temperatures and reduced pressures_________________?

Related Mcqs:

1. Under conditions of equal reduced pressure and equal reduced temperature, substances are said to be in the ‘corresponding states’. At equal reduced conditions i.e., at the corresponding state, the ____________ of different gases are nearly the same?

   A. Compressibility
   B. Molecular weight
   C. Humidity
   D. None of these

2. If two gases have same reduced temperature and reduced pressure, then they will have the same____________________?

   A. Volume
   B. Mass
   C. Critical temperature
   D. None of these

3. At higher temperatures, molal heat capacities for most of the gases (at constant pressure) _______________ with increase in temperature?

   A. Varies linearly
   B. Increases
   C. Decreases
   D. Does not vary

4. Near their critical temperatures, all gases occupy volumes _____________ that of the ideal gas?

   A. Less than
   B. Same as
   C. More than
   D. Half

5. With increase in reduced temperature, the fugacity co-efficient of a gas at constant reduced pressure___________________?

   A. Increases
   B. Decreases
   C. Remain same
   D. Decreases linearly

6. Compressibility factor-reduced pressure plot on reduced co-ordinates facilitates__________________?

   A. Use of only one graph for all gases
   B. Covering of wide range
   C. Easier plotting
   D. More accurate plotting

7. Except for monatomic gases, the molal heat capacity at constant volume for all gases is _____________ Kcal/Kg mole.° K?

   A. 3
   B. > 3
   C. < 3
   D. < 1

8. Which of the following gases is having the widest explosion limit (about 2 to 81% gas in gasair mixture), rendering it the property of the most explosive gas ?

   A. Hydrogen
   B. Acetylene
   C. Carbon monoxide
   D. Ammonia

9. The equilibrium constant for a chemical reaction at two different temperatures is given by__________________?

   A. Kp2/Kp1 = – (ΔH/R) (1/T2 – 1/T1)
   B. Kp2/Kp1 = (ΔH/R) (1/T2 – 1/T1)
   C. Kp2/Kp1 = ΔH (1/T2 – 1/T1)
   D. Kp2/Kp1 = – (1/R) (1/T2 – 1/T1)

10. What is the value of maximum COP in case of absorption refrigeration, if refrigeration provided is at temperature, TR (where, T1 and T2 are source & surrounding temperatures respectively.) ?

    A. TR/(T2 – TR) × (T1 – T2)/T1
    B. TR/(T2 – TR) × T1/(T1 – T2)
    C. TR/(T1 – TR) × (T1 – T2)/T1
    D. None of these