A. 5
B. 6
C. 7
D. 12
Let one of the numbers be “x”; then the other is “x+5”.
Equation:
x + x+5 = 19
2x = 14
x = 7 (the 1st number)
x+5 = 12 (the other number)
Related Mcqs:
- If the sum of two numbers is 55 and the H.C.F and L.C.M of these numbers are 5 and 120 respectively, then the sum of the reciprocal of the numbers is equal to___________?
A. 55/601
B. 601/55
C. 11/120
D. 120/11 - A man invests a certain sum of money at 6% per annum simple interest and another sum at 7% per annum simple interest. His income from interest after 2 years was Rs. 354. One-forth of the first sum is equal to one-fifth of the second sum. The total sum invested was :
A. Rs.3100
B. Rs.2700
C. Rs.2200
D. Rs.1800 - The sum of five numbers is 655. The average of the first two numbers is 85 and the third number is 125. Find the average of the two numbers?
A. 180
B. 170
C. 190
D. 175 - The L.C.M of two numbers is 48. The numbers are in the ratio 2:3. The sum of numbers is__________?
A. 28
B. 32
C. 40
D. 64 - The sum of the squares of three numbers is 138, while the sum of their products taken two at a time is 131. Their sum is :___________?
A. 20
B. 30
C. 40
D. None of these - If the sum of two numbers is 33 and their difference is 15, the smaller number is :__________?
A. 9
B. 12
C. 15
D. 18 - Two numbers are in the ratio 3 : 5. If 9 is subtracted from each, the new numbers are in the ratio 12 : 23. The smaller number is :________?
A. 27
B. 33
C. 49
D. 55 - The average of 1st 3 of 4 numbers is 16 and of the last 3 are 15. If the sum of the first and the last number is 13. What is the last numbers?
A. 8
B. 6
C. 5
D. 2 - The H.C.F and L.C.M of two numbers are 84 and 21 respectively. If the ratio of the two numbers is 1:4, then the larger of the two numbers is____________?
A. 12
B. 48
C. 84
D. 108 - The L.C.M of two numbers is 495 and their H.C.F is 5. If the sum of the numbers is 10, then their difference is__________?
A. 10
B. 46
C. 70
D. 90
33 Comments
Option C. 7 is correct Answer
c. 7
admin:-make the answer bold.
answer nahe likha
Let’s assume that the smaller number is x.According to the problem, the larger number exceeds the smaller number by 5. So the larger number is (x 5).Also, the sum of the numbers is 19.Therefore, we can write an equation as:x (x 5) = 19Simplifying the equation, we get:2x 5 = 19Subtracting 5 from both sides, we get:2x = 14Dividing both sides by 2, we get:x = 7So, the smaller number is 7.
7
6
Sar mojhy abhi tayari Karni he
C
Very good
I think answer is 7 because this is smaller
Answer is 7 because this is a smaller
7
x+(x+5)=19
2x+5=19
2x=19-5
2x=14
x=07
check
7+7+5=19
Let’s solve the problem step by step.
Let’s assume the smaller number is x.
According to the given information, the larger number exceeds the smaller number by 5. Therefore, the larger number is x + 5.
The sum of the numbers is 19. So, we can write the equation as:
x + (x + 5) = 19
2x + 5 = 19
2x = 19 – 5
2x = 14
x = 14 / 2
x = 7
So, the smaller number is 7
7
5
7
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Ans is 7. And 12
Statistics
you have been want to give more than questions from 10
7
Ans is 7
answer 7
x + x + 5 = 19
7 is correct answer
x-y=5, x+y=19, subtract the two equations, 2x=24, x=12, therefore, y=7.
7 is correct answer
7
7
Let’s denote the smaller number as \( x \) and the larger number as \( y \).
According to the problem:
– \( y \) exceeds \( x \) by 5, so we have the equation:
\[
y = x + 5
\]
– The sum of the numbers is 19, so we have another equation:
\[
x + y = 19
\]
Now substitute \( y = x + 5 \) into the second equation:
\[
x + (x + 5) = 19
\]
Combine like terms:
\[
2x + 5 = 19
\]
Subtract 5 from both sides to isolate the term with \( x \):
\[
2x = 14
\]
Divide both sides by 2 to solve for \( x \):
\[
x = \frac{14}{2} = 7
\]
So, the smaller number \( x \) is \( \boxed{7} \).
To find the larger number \( y \):
\[
y = x + 5 = 7 + 5 = 12
\]
Therefore, the larger number \( y \) is \( \boxed{12} \).
To verify:
– The larger number \( y = 12 \) indeed exceeds the smaller number \( x = 7 \) by 5.
– The sum of \( x \) and \( y \) is \( 7 + 12 = 19 \), which matches the given condition.
Thus, the solution \( \boxed{7} \) for the smaller number is correct.
Thanks for All of you for pointing out the correct answer.