A. 8
B. 6
C. 5
D. 2
A + B + C = 48
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B + C + D = 45
A + D = 13
A – D = 3
A + D = 13
2D = 10
D = 5
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5 Comments
let the four numbers be a,b,c,d
Given that
a+b+c= 48 ……I
b+c+d= 45 ……II
adding these two equations we get
a+d+2(c+b) = 93
given that a+d = 13, we get
c+b = 40 Substituting in eq II, we get
d = 5