A. 0.2 to 0.8
B. 5 to 25
C. 50 to 100
D. 100 to 250
Related Mcqs:
- Vibrating screens are used for handling large tonnages of materials. The vibrating motion is imparted to the screening surface by means of_____________________?
A. Electromagnets
B. Cams or eccentric shafts
C. Unbalanced flywheels
D. Either A., B. or C. - Higher is the mesh number, smaller will be the aperture size of the screen. It means that the aperture size of a 200 mesh screen will be smaller than that of 20 mesh screen. This is valid for__________________?
A. British standard screens
B. German standard screens (DIN 1171) etc
C. American standard screens (ASTM and Tyler standard screens)
D. All A., B. and C. - For Indian standard (IS) screens, the mesh number is equal to its aperture size expressed to the nearest deca-micron (0.01 mm). Aperture width of IS screen of mesh number 50 will be approximately _____________ microns?
A. 5
B. 50
C. 500
D. 5000 - Pulverised coal passing through 200 mesh screen has a diameter of 0.074 mm (74 micron). The same passing through 50 mesh screen will have a dia of ____________ mm?
A. 0.007
B. 0.30
C. 50
D. 0.014 - With increase in the capacity of screens, the screen effectiveness__________________?
A. Remains unchanged
B. Increases
C. Decreases
D. Decreases exponentially - Which of the following screens has the maximum capacity ?
A. Grizzlies
B. Trommels
C. Shaking screen
D. Vibrating screen - Trommels are revolving screens which normally operate in the range of _______________ rpm?
A. 1 – 2
B. 15 – 20
C. 40 – 50
D. 60 – 75 - Capacity (in tons/hr) of jaw/gyratory crusher is equal to (where, L = length of the receiving opening, cm S = greater width of the discharge opening, cm) ?
A. 0.01 L.S
B. 0.087 L.S
C. L.S
D. L.S/0.087 - Theoretical capacity of crushing rolls in tons/hr is given by (where, V = peripheral velocity, m/sec. W = width of rolls, m Dr = distance between rolls ρ = density of material to be crushed, kg/m3 here, V =πND where, N = speed of the rolls in rotation per second (rps) D = diameter of rolls, m) ?
A. 3.6 V.W.Dr.ρ
B. 3.6 V.W. ρ
C. 3.6 W.Dr.ρ
D. 3.6 V.W.Dr/ρ - Capacity of flight conveyor in tons/hr is given by (where, W & D = width and depth of flight respectively in metre V = speed of the conveyor, metre/second ρ = bulk density of material, kg/m3) ?
A. 3.6 W.D.V.ρ
B. 3.6 W.D.V
C. 3.6 W.V.ρ
D. 3.6 D.V.ρ