A. 22N
B. 16N
C. 20N
D. 4N
Submitted by: Huzaifa Naseer
Mass ,m=0.2kg
Total height, h=0.2+2=2.2m
Work done =Difference in potential energy.
F.S=mgh where S is the distance for e hich the force is applied by hand,
S=0.2m
F=
S
mgh
=
0.2
0.2×10×2.2
F=22N
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Mass ,m=0.2kg
Total height, h=0.2+2=2.2m
Work done =Difference in potential energy.
F.S=mgh where S is the distance for ehich the force is applied by hand,
S=0.2m
F=
S
mgh
=
0.2
0.2×10×2.2
F=22N
Correct option is AMass m is 0.2kgTotal height, h=0.2 2=2.2mWork done =Difference in potential energy.F.S=mgh where S is the distance for which the force is applied by hand,S=0.2mF=mgh/S=0.2×10×2.2/0.2F=22N
Mass ,m=0.2kg
Total height, h=0.2+2=2.2m
Work done =Difference in potential energy.
F.S=mgh where S is the distance for e hich the force is applied by hand,
S=0.2m
F=
S
mgh
=
0.2
0.2×10×2.2
F=22N