Ultra centrifuges are used for the separation of _____________ solid particles?

Related Mcqs:

1. Number of particles in a crushed solid sample is given by (where, m = mass of particles in a sample, Vp = volume of one particle, ρ= density of particles) ?

   A. m/ρ . Vp
   B. m . ρ/Vp
   C. m . Vp/ρ
   D. Vp/m . ρ

2. ______________ are used for the separation of coarse particles from a slurry of fine particles?

   A. Thickeners
   B. Classifiers
   C. Hydrocyclones
   D. Decanters

3. Separation of a suspension or slurry into a supernatant clear liquid (free from particles) and a thick sludge containing a high concentration of solid is called__________________?

   A. Classification
   B. Sedimentation
   C. Clarification
   D. Decantation

4. Solid particles separation based on the difference in their flow velocities through fluids is termed as the__________________?

   A. Clarification
   B. Classification
   C. Elutriation
   D. Sedimentation

5. Separation of solid particles based on their densities is called_________________?

   A. Sizing
   B. Sorting
   C. Clarification
   D. Dispersion

6. Tabular bowl centrifuges as compared to disk bowl centrifuges___________________?

   A. Operate at higher speed
   B. Employ bowl of larger diameter
   C. Can’t be operated under pressure/vacuum
   D. Can’t be used for separation of fine suspended solids from a liquid

7. Separation of particles of various sizes, shapes and densities by allowing them to settle in a fluid is called__________________?

   A. Classification
   B. Froth floatation
   C. Thickening
   D. Clarification

8. Sorting classifiers employing differential settling methods for separation of particles make use of the differences in their_________________?

   A. Particle sizes
   B. Densities
   C. Terminal velocities
   D. None of these

9. Separation of solid suspended in liquid into a supernatant clear liquid and a denser slurry employs a process termed as the___________________?

   A. Coagulation
   B. Flocculation
   C. Sedimentation
   D. Clarification

10. The energy required per unit mass to grind limestone particles of very large size to 100 μm is 12.7 kWh/ton. An estimate (using Bond’s law) of the energy to grind the particles from a very large size to 50 μm is________________?

    A. 6.35 kWh/ton
    B. 9.0 kWh/ton
    C. 18 kWh/ton
    D. 25.4 kWh/ton