Separation of a suspension or slurry into a supernatant clear liquid (free from particles) and a thick sludge containing a high concentration of solid is called__________________?

Related Mcqs:

1. Separation of solid suspended in liquid into a supernatant clear liquid and a denser slurry employs a process termed as the___________________?

   A. Coagulation
   B. Flocculation
   C. Sedimentation
   D. Clarification

2. ______________ are used for the separation of coarse particles from a slurry of fine particles?

   A. Thickeners
   B. Classifiers
   C. Hydrocyclones
   D. Decanters

3. ______________ is used for producing a thick suspension from a thin slurry?

   A. Cartridge filter
   B. Rotary drum vacuum filter
   C. Pressure filter thickener
   D. Plate and frame filter press

4. Number of particles in a crushed solid sample is given by (where, m = mass of particles in a sample, Vp = volume of one particle, ρ= density of particles) ?

   A. m/ρ . Vp
   B. m . ρ/Vp
   C. m . Vp/ρ
   D. Vp/m . ρ

5. Separation of particles of various sizes, shapes and densities by allowing them to settle in a fluid is called__________________?

   A. Classification
   B. Froth floatation
   C. Thickening
   D. Clarification

6. Ultra centrifuges are used for the separation of _____________ solid particles?

   A. Coarse
   B. Fine
   C. Colloidal
   D. Dissolved

7. Solid particles separation based on the difference in their flow velocities through fluids is termed as the__________________?

   A. Clarification
   B. Classification
   C. Elutriation
   D. Sedimentation

8. Separation of solid particles based on their densities is called_________________?

   A. Sizing
   B. Sorting
   C. Clarification
   D. Dispersion

9. A suspension of glass beads in ethylene glycol has a hindered settling velocity of 1.7 mm/s, while the terminal settling velocity of a single glass bead in ethylene glycol is 17 mm/s. If the Richardson-Zaki hindered settling index is 4.5, the volume fraction of solids in the suspension is_____________?

   A. 0.1
   B. 0.4
   C. 0.6
   D. None of these

10. The basic filtration equation is given as dt/dV = (μ/A ΔP). [(α .CV/A) + Rm], where, V is volume of the filtrate; A is the filtration area, a is specific cake resistance, μ is viscosity of the filtrate, and C is the concentration of the solids in the feed slurry. In a 20 minutes constant rate filtration, 5 m3 of filtrate was obtained. If this is followed by a constant pressure filtration, how much more time in minutes, it will take for another 5 m3 of filtrate to be produced? Neglect filter medium resistance, Rm; assume incompressible cake ?

    A. 10
    B. 20
    C. 25
    D. 30