A. Decreases
B. Increases
C. Remains unchanged
D. May increase or decrease; depends on the machine
Related Mcqs:
- Maximum size reduction in a fluid energy mill is achieved by___________________?
A. Compression
B. Interparticle attrition
C. Cutting
D. Impact - Kick’s law assumes that the energy required for size reduction is proportional to the logarithm of the ratio between the initial and the final diameters. The unit of Kick’s constant is_________________?
A. kW. sec/kg
B. kWh/kg
C. kWh/sec. kg
D. kg/sec - During size reduction by a jaw crusher, the energy consumed decreases with the__________________?
A. Decreasing size of product at constant size of feed
B. Decreasing machine capacity
C. Increasing size of feed at constant reduction ratio
D. None of these - Which of the following achieves the least reduction ratio for a given feed size ?
A. Jaw crusher
B. Roll crusher
C. Cone crusher
D. Gyratory crusher - Which of the following equations is Rittinger’s crushing law? (Where P = power required by the machine, m = feed rate, k = a constant, D̅ sa & D̅ sb = volume surface mean diameter of feed & product respectively) ?
A. P/m = K/ √Dp
B. P/m = K . ln D̅ sa/D̅ sb
C. P/m = K . (1/ D̅ sb – 1/D̅ sa)
D. None of these - In a size reduction crushing operation, feed size is 100 to 300 mm. while the product size is 10 to 50 mm. This is a case of the _____________ crushing?
A. Primary
B. Secondary
C. Fine
D. Ultrafine - Size reduction of _____________ is accomplished in steam heated rollers and roll crushers?
A. Resins
B. Gums
C. Hard rubber
D. Waxes - The energy required per unit mass to grind limestone particles of very large size to 100 μm is 12.7 kWh/ton. An estimate (using Bond’s law) of the energy to grind the particles from a very large size to 50 μm is________________?
A. 6.35 kWh/ton
B. 9.0 kWh/ton
C. 18 kWh/ton
D. 25.4 kWh/ton - In a roll crusher, the specific power consumption and the production rate is affected by the_________________?
A. Reduction ratio
B. Differential roll speed
C. Both A. and B.
D. Neither A. nor B. - The basic filtration equation is given as dt/dV = (μ/A ΔP). [(α .CV/A) + Rm], where, V is volume of the filtrate; A is the filtration area, a is specific cake resistance, μ is viscosity of the filtrate, and C is the concentration of the solids in the feed slurry. In a 20 minutes constant rate filtration, 5 m3 of filtrate was obtained. If this is followed by a constant pressure filtration, how much more time in minutes, it will take for another 5 m3 of filtrate to be produced? Neglect filter medium resistance, Rm; assume incompressible cake ?
A. 10
B. 20
C. 25
D. 30
