A. 6.V/D.S
B. V/6D.S
C. D.S/V
D. V/D.S
Related Mcqs:
- Sphericity is the ratio of the surface area of a spherical particle having the same volume as the particle to the surface area of the particle. Which of the following has the maximum value of sphericity ?
A. Sphere
B. Cube
C. Cylinder (L/D = 1)
D. Raschig rings - If dp is the equivalent diameter of a non-spherical particle, Vp its volume and sp its surface area, then its sphericity is φs is defined by________________?
A. φs = 6 Vp/dpsp
B. φs = Vp/dpsp
C. φs = 6 dpSp/Vp
D. φs = dpSp/Vp - Sphericity of a cubical particle, when its equivalent diameter is taken as the height of the cube, is ________________ ?
A. 0.5
B. 1
C. √2
D. √3 - The specific surface of spherical particles is given by (where D and ρ are diameter and density of particle) ?
A. 6/D.ρ
B. 2/D.ρ
C. 4/D.ρ
D. 12/D.ρ - The specific surface of spherical particles is proportional to (where, Dp = diameter of particle)?
A. D2
B. Dp
C. 1/Dp
D. 1/D2p - Equivalent diameter of a particle is the diameter of the sphere having the same __________________?
A. Ratio of surface to volume as the actual volume
B. Ratio of volume to surface as the particle
C. Volume as the particle
D. None of these - According to Bond crushing law, the work required to form particle of size ‘D’ from very large feed is (where (S/V)p and (S/V)f are surface to volume ratio of the product and feed respectively) ?
A. (S/V)p
B. √(S/V)p
C. (S/V)2p
D. (S/V)f - For a non-spherical particle, the sphericity__________________?
A. Is defined as the ratio of surface area of a sphere having the same volume as the particle to the
actual surface area of the particle
B. Has the dimension of length
C. Is always less than 1
D. Is the ratio of volume of a sphere having the same surface area as the particle to the actual
volume of the particle - The sphericity of a solid particle of cubical shape is ___________________?
A. π
B. (π/6)1/3
C. (π/6)1/2
D. π/3 - Which of the following equations is Rittinger’s crushing law? (Where P = power required by the machine, m = feed rate, k = a constant, D̅ sa & D̅ sb = volume surface mean diameter of feed & product respectively) ?
A. P/m = K/ √Dp
B. P/m = K . ln D̅ sa/D̅ sb
C. P/m = K . (1/ D̅ sb – 1/D̅ sa)
D. None of these
