A. 38
B. 40
C. 44
D. 48
Let the speed of the faster train be x miles per hour and
the distance travelled by it when it meets the slower train be y miles. Time taken by the faster train to cover y miles
= Time taken by the slower train to cover (287-y) miles
= 3.5 hours (y/x) = (287-y)/(x-6) = 3.5 Solving, x = 44 miles/hr
Related Mcqs:
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