A. If x < y
B. If x > y
C. If x ≤ y
D. If x ≥ y
Explanation:
I. x2 + 6x + 5x + 30 = 0
=>(x + 6)(x + 5) = 0 => x = -6, -5
II. y2 + 8y + 7y + 56 = 0
=>(y + 8)(y + 7) = 0 => y = -8, -7
=> x > y
Related Mcqs:
- (i). a2 – 7a + 12 = 0,
(ii). b2 – 3b + 2 = 0 to solve both the equations to find the values of a and b?A. if a < b
B. if a ≤ b
C. if the relationship between a and b cannot be established.
D. if a > b - (i). a2 – 9a + 20 = 0,
(ii). 2b2 – 5b – 12 = 0 to solve both the equations to find the values of a and b?A. If a < b
B. If a ≤ b
C. If the relationship between a and b cannot be established
D. If a ≥ b - I. a2 + 8a + 16 = 0,
II. b2 – 4b + 3 = 0 to solve both the equations to find the values of a and b?A. If a < b
B. If a ≤ b
C. If the relationship between a and b cannot be established
D. If a > b - I. x2 + 5x + 6 = 0,
II. y2 + 9y +14 = 0 to solve both the equations to find the values of x and y?A. If x < y
B. If x > y
C. If x ≤ y
D. If x = y or the relationship between x and y cannot be established. - I. x2 – x – 42 = 0,
II. y2 – 17y + 72 = 0 to solve both the equations to find the values of x and y?A. If x < y
B. If x > y
C. If x ≤ y
D. If x ≥ y
E. If x = y or the relationship between x and y cannot be established. - I. x2 + 9x + 20 = 0,
II. y2 + 5y + 6 = 0 to solve both the equations to find the values of x and y?A. If x < y
B. If x > y
C. If x ≤ y
D. If x ≥ y - I. x2 + 3x – 18 = 0,
II. y2 + y – 30 = 0 to solve both the equations to find the values of x and y?A. If x < y
B. If x > y
C. If x ≤ y
D. If x ≥ y
E. If x = y or the relationship between x and y cannot be established. - I. 9a2 + 18a + 5 = 0,
II. 2b2 + 13b + 20 = 0 to solve both the equations to find the values of a and b?A. If a > b
B. If a ≥ b
C. If a < b
D. If a ≤ b - I. a3 – 988 = 343,
II. b2 – 72 = 49 to solve both the equations to find the values of a and b?A. If a > b
B. If a ≥ b
C. If a < b
D. If a ≤ b - I. a2 – 13a + 42 = 0,
II. b2 – 15b + 56 = 0 to solve both the equations to find the values of a and b?A. If a > b
B. If a ≥ b
C. If a < b
D. If a ≤ b.