A. 4 volt
B. 5 volt
C. 2 volt
D. 0.4 volt
Related Mcqs:
- A sensitive galvanometer gives full-scale deflection with 100 mV. If the resistance of the galvanometer is 50? the maximum current that can flow through safely is__________________?
A. 2.0 mA
B. 20 mA
C. 200 mA
D. 0.2 mA - The deflection for 50 division of galvanometer is decreased to 25 divisions by shunt resistance of 12Ω. Galvanometer resistance is_____________?
A. 18Ω
B. 30Ω
C. 24Ω
D. 12Ω - An inductive coil has a resistance of 100Ω. When an AC signal of frequency 1000Hz is fed to the coil the applied voltage leads the current by 45Ω. What is the inductance of the coil ?
A. 10mH
B. 12mH
C. 16mH
D. 20mH - Coil of a galvanometer is suspended in a radial magnetic field so that the deflecting torque on the coil is always___________________?
A. BINA cosa
B. BINA sina
C. BINA tana
D. BINA - The effective way to increase the sensitivity of a moving coil galvanometer is to___________________?
A. use a very long and fine suspension
B. use a coil of very large area
C. use a coil with very large number of turns
D. use a very strong magnetic field - When a pure inductor of inductance L and a pure capacitor of capacitance C are connected in parallel to a sinusoidal potential difference V the potential difference across both L & C will be_______________?
A. Same
B. Different
C. At L will be more than at C
D. At L will be less than at C - When the coil of the galvanometer is in equilibrium then the deflecting couple is____________________?
A. zero
B. equal to the restoring couple
C. greater than the restoring couple
D. smaller than the restoring couple - Minimum current required to produce a deflection of 1 mm on a scale at a distance of 1 meter is__________________?
A. 0.1 A
B. 1:00 AM
C. current sensitivity
D. 1 m A - A capacitor of capacitance 30µF is charged by a constant current of 10mA. If initially, the capacitor was uncharged what is the time taken for the potential difference across the capacitor to reach 300V ?
A. 0.9sec
B. 15 sec
C. 1.5x105sec
D. 0.9x102sec - n an LCR series circuit, if V is the effective value of the applied voltage VR is the voltage across R VL is the effective voltage across L & Vc is the effective voltage across C then_______________?
IA. V = VR+VL+VC
B. V2 = VR2+VL2+VC2
C. V2 = VR2+(VL-VC)2
D. V2 = VL2+(VR-VC)2
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