A. Sublimation
B. Vaporisation
C. Melting
D. Either A, B. or C.
Related Mcqs:
- Gibbs free energy (G) is represented by, G = H – TS, whereas Helmholtz free energy, A. is given by, A = E – TS. Which of the following is the Gibbs-Helmholtz equation ?
A. [∂(G/T)/∂T] = – (H/T2)
B. [∂(A/T)/∂T]V = – E/T2
C. Both A. and B.
D. Neither A. nor B. - The change in Gibbs free energy for vaporisation of a pure substance is___________________?
A. Positive
B. Negative
C. Zero
D. May be positive or negative - Chemical potential (an intensive property) of a substance is a force that drives the chemical system to equilibrium and is equal to its partial molar properties. The ratio of chemical potential to free energy of a pure substance at constant temperature and pressure is________________?
A. 0
B. 1
C. ∞
D. None of these - Gibbs free energy per mole for a pure substance is equal to the__________________?
A. Latent heat of vaporisation
B. Chemical potential
C. Molal boiling point
D. Heat capacity - The molar excess Gibbs free energy, gE, for a binary liquid mixture at T and P is given by, (gE/RT) = A . x1. x2, where A is a constant. The corresponding equation for ln y1, where y1 is the activity co-efficient of component 1, is__________________?
A. A . x22
B. Ax1
C. Ax2
D. Ax12 - Gibbs free energy of a pure fluid approaches _____________ as the pressure tends to zero at constant temperature?
A. Infinity
B. Minus infinity
C. Zero
D. None of these - The standard Gibbs free energy change of a reaction depends on the equilibrium______________________?
A. Pressure
B. Temperature
C. Composition
D. All A, B. and C - The chemical potential for a pure substance is ____________ its partial molal free energy?
A. More than
B. Less than
C. Equal to
D. Not related to - At constant temperature and pressure, for one mole of a pure substance, the ratio of the free energy to the chemical potential is____________________?
A. Zero
B. One
C. Infinity
D. Negative - Gibbs free energy (F) is defined as__________________?
A. F = E – TS
B. F = H – TS
C. F = H + TS
D. F = E + TS